$\sec^2x+1=\frac{1}{\sin\left(x\right)^2}$
$\left(\frac{w}{2}-\frac{z}{3}\right)^2$
$\int\left(2x-1\right)^2e^{-3x}dx$
$27m^6+64n^9$
$6-\left(-4\right)-2$
$\log\left(3\right)\left(7x+3\right)=\log\left(3\right)\left(5x+9\right)$
$+\left(-4.1\right)\left(+1\right)$
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