$1+18x+81x^2$
$5=x^2-4$
$\frac{x^2+7x+6}{x^2-5x-6}$
$4\left(2x+3\right)-7x$
$y^{12}\cdot y^{10}$
$\frac{x^2+3x-2}{x+3}$
$\int\frac{\left(4x^2-5x+6\right)}{x-3}dx$
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