$\frac{v}{3}-6=-15$
$9\:x\:\left(3y\right)$
$47\:-\left(-68\right)$
$\left(2-3\right)+\left(6-5\right)-8-9\left(4-6\right)-5\left(6-8\right)$
$10\:=\:10\:\cdot\:\log_{10}\left(x\right)$
$\frac{d}{dx}\left(2xy+x^2=y\right)$
$-7-8-7+3-5$
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