12∫25−4x2dx\frac{1}{2}\int\frac{2}{5-4x^2}dx21∫5−4x22dx
∫x1+2x32dx\int\frac{x}{\sqrt[3]{1+2x}}^2dx∫31+2xx2dx
f2−5f−24f^2-5f-24f2−5f−24
(3−2d5)(3+2d5)\left(3-2d^5\right)\left(3+2d^5\right)(3−2d5)(3+2d5)
5∫sin(x)⋅cos(x)dx5\int\sin\left(x\right)\cdot\cos\left(x\right)dx5∫sin(x)⋅cos(x)dx
−10 ⋅2\:-10\:\cdot2−10⋅2
2x2x+4=3xx+2\frac{2x}{2x+4}=\frac{3x}{x+2}2x+42x=x+23x
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