$f\left(x\right)=\left(x^2-6\right)^3$
$\left(\frac{2}{3}-3x\right)^2$
$x^2=\frac{c}{y}$
$f\left(x\right)=\left(x+3\right)^2\left(x+2\right)$
$-8y+12xy-3y$
$x+\frac{10}{x}=6$
$10^2+y^4-14y-24$
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