$x^2\le4x-3$
$\lim_{x\to\infty}xe^x$
$5n\:+\:3\:+\:8n$
$\sqrt[3]{\left(8\right).\:27.\:64}$
$2\left(\frac{b}{3}\right)\left(5a\right)$
$\int e^{xy^2}dx$
$2g+\left(-4g\right)$
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