1−12x2y′=x\sqrt{1-12x^2}y'=x1−12x2y′=x
m+n+p=0 m+n+p=0\:m+n+p=0
∫(16+x2)−6dx\int\left(16+x^2\right)^{-6}dx∫(16+x2)−6dx
dydx(cxy−cx−cy+c=0)\frac{dy}{dx}\left(cxy-cx-cy+c=0\right)dxdy(cxy−cx−cy+c=0)
dydx=ycos5x\frac{dy}{dx}=ycos5xdxdy=ycos5x
(+43)−(−15)\left(+43\right)-\left(-15\right)(+43)−(−15)
∫cos(x)sen8(x)dx\int cos\left(x\right)sen^8\left(x\right)dx∫cos(x)sen8(x)dx
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