$-x=18$
$\int_0^4\left(\frac{3x-6}{2}\right)dx$
$\left(-5\right).14+\left(-5\right).6$
$\frac{4y}{2x^4y^2}$
$\int\frac{1}{x^4}dx$
$\lim_{x\to0}\left(\frac{x^2-6x}{x^2-4}\right)$
$y\:=\:sin^4x\cdot\frac{tan^6x}{\left(x^2+3\right)^2}$
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