$1-0.38$
$\frac{x^2+8x+12}{x^2+3-18}$
$\left(3x+7\right)^4\cdot\left(4x\right)$
$7-3\cdot1$
$\frac{4x-3}{2}\ge x+1$
$\left(4m-1\right)^3$
$20x^3-50x^2-30x-0$
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