$\frac{d^2}{dx^2}\left(\left(2x+3\right)^5\right)$
$\:\:-\:\left[\:\left(5.604\right)\:-\:\left(7.817\right)\:\right]\:-\:\left[\:\left(13.421\right)\:-\:\left(-35\right)\:\right]\:-\:\left(71\right)\:$
$x^2+7x-15$
$-16-\left(-7\right)$
$3x^4+2x^3-5x^2+7x$
$f\left(x\right)=\frac{x-1}{x^2-3x+2}$
$\left(1-x-x^2\right)^2$
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