((x2+1)2x2)\left(\frac{\left(x^2+1\right)^2}{x^2}\right)(x2(x2+1)2)
x2−14x−120x^2-14x-120x2−14x−120
0,25 ⋅ 0,00070,25\:\cdot\:0,00070,25⋅0,0007
8x2+2y2−16x+8y+14=08x^2+2y^2-16x+8y+14=08x2+2y2−16x+8y+14=0
∫ 1x(x+x)dx\int\:\:\frac{1}{\sqrt{x}\left(x+\sqrt{x}\right)}dx∫x(x+x)1dx
−(x+3)(x+5)-\left(x+3\right)\left(x+5\right)−(x+3)(x+5)
−x+3y=5-x+3y=5−x+3y=5
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