$-3x+y;\:x=2;\:y=6$
$\tan\left(30\right)+\sin\left(\frac{\pi}{4}\right)$
$\left(64-y^3\right)$
$4x-1=-9$
$\frac{\left(2v+4+4\sqrt{x}\right)\left(v+2-2\right)\sqrt{x}}{6v^3+8v^2-8v}$
$y^2+3x^2+5=0$
$\frac{dy}{dx}=\frac{x+x^2}{y-y^2}$
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