∫(8x+16)(2x2+8x−3)4dx\int\left(8x+16\right)\left(2x^2+8x-3\right)^4dx∫(8x+16)(2x2+8x−3)4dx
limx→2(6x2−15x+66x2−12x+5)\lim_{x\to2}\left(\frac{6x^2-15x+6}{6x^2-12x+5}\right)x→2lim(6x2−12x+56x2−15x+6)
m2−4m+2m^2-4m+2m2−4m+2
limx→0(1x+1−11−x22x)\lim_{x\to0}\left(\frac{\frac{1}{x+1}-\frac{1}{\sqrt{1-x^2}}}{2x}\right)x→0lim(2xx+11−1−x21)
(x2+9x−40)\left(x^2+9x-40\right)(x2+9x−40)
limx→∞(ln(2x+1))\lim_{x\to\infty}\left(ln\left(2x+1\right)\right)x→∞lim(ln(2x+1))
4cos(2π6+π3)4cos\left(2\frac{\pi}{6}+\frac{\pi}{3}\right)4cos(26π+3π)
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