$70\cdot50$
$4.x+3=39$
$3x+5a-2x+3a$
$3679\cdot36$
$\left(1+x^2\right)^5\frac{dy}{dx}\:=\:x;y\left(0\right)=1$
$a^2x^3-a^2y^3+2ax^3-2ay^4$
$\frac{x\left(x-3\right)\left(4x-1\right)\left(x+4\right)}{\left(x+3\right)\left(13x+12\right)}$
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