$e^{3y}dx+\frac{y}{x^2}dy=0$
$4h-2e^2+6,\:para\:h=-2\:y\:e=-1$
$\left(-5b^2+8ab+a^2\right)-\left(3a^2+ab-6b^2\right)$
$3x^2+12x+81=15$
$\left(4x+13\right)\left(4x+13\right)$
$3x^2+4y+2x^2-2y$
$\frac{\left(x^2+3x+2\right)}{\left(x^2+6x+8\right)}$
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