$\sqrt{a^4}$
$16 \cdot 2 ^ { 3 } + 4 - 2$
$-12j\:-\:4k\:+\:5j\:+\:k$
$-5+0.25$
$\frac{1}{y^2}dy=-2xdx$
$\int_0^4\left(\arctan\left(\sqrt{x}\right)\right)dx$
$\int_1^{\infty}\left(\frac{1}{2n^2+1}\right)dx$
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