$\int\:\frac{4x-1}{\left(4x^2-2x+3\right)^5}\:dx$
$\lim_{t\to0}\:\frac{1}{2}\left|t\right|+t$
$\int\frac{1}{\left(x-1\right)\left(x+1\right)\left(x-2\right)}dx$
$\lim_{x\to-3}3x$
$2^2-3z$
$\frac{x}{x+2}<4$
$\left(2x^5+x^4+3x\right)+\left(5x^5+4x^3-x\right)$
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