$5x^2=\left(2x^2+3x^4\right)$
$3\left(5a-3\right)+6a$
$-18\cdot\left(-20\cdot18\right)$
$\frac{xdx}{dt}+4t=14$
$\frac{1+\sec\left(b\right)}{1-\sec\left(b\right)}$
$\lim_{x\to+1}\left(\frac{1-\cos\left(x\right)}{x^2}\right)$
$\lim_{x\to0}\left(sin\left(9x\right)\right)$
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