$x^2+8x=20$
$\int\left(2x+3\right)\left(2x^2+6x+1\right)^8dx$
$\left(1-a^2\right)^4$
$625\cdot128$
$\frac{2\frac{1}{2}+3}{\sqrt[2]{1-2\frac{1}{2}}}$
$\lim_{x\to0.1}\left(\frac{x}{\sin\left(x\right)}\right)$
$6\cdot m^5\cdot\frac{1}{m}$
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