$\left(2x^2-8y^2\right)$
$\int\theta\:\sec\left(x^2\right)d\theta\:$
$\frac{3x^4-2x^3-x+2}{x-3}$
$\frac{x}{8}-36=15$
$\sin\left(3x\right)\left(2\cos\left(2x\right)\right)+\sin\left(2x\right)\left(3\cos\left(3x\right)\right)$
$5x+2y-3x+4$
$\frac{dy}{dx}=\frac{x^2+y^2-2x}{2y}$
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