$x^2-25y^2$
$3x^2+x-24$
$\frac{x^2-6x-4}{x-1}$
$\int\sec^3\left(x\right)\tan^5\left(x\right)dx$
$\left(2x^2+6y\right)^2$
$\frac{m}{5m-20}=\frac{1}{m-7}$
$\left(m-n+p\right)-\left(3n+4m+5p\right)\:$
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