$\frac{d^2}{dx^2}\left(\:x^2+y^2=4\right)$
$\frac{x^3+x^2-2x}{x+2}$
$\lim_{x\to3}\left(5x^3+2x^2-x^3\right)$
$\left(2u-3\right)\left(2u-2\right)$
$.93+.76+.08+8.3+.12$
$\tan^2\left(x\right)+1=\left(5\right)$
$\int8y\sqrt{y+9}dy$
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