$2\frac{8}{9}x\frac{1}{2}$

$3+4^2:\left(-2\right)-\left(4-3^0\right)$

$\int\left(\frac{\sin^2\left(x\right)}{\sin^2\left(x\right)\cos^2\left(x\right)}\right)dx$

$\lim_{x\to3}\:x^2+3x$

$\frac{3+\sin^2\left(x\right)}{\cos\left(x\right)-2}=3\cos\left(x\right)$

$\int x^{-\frac{3}{7}}dx$

$3x-7<-2$