$4x+3x-5x-7x+3x$
$-\frac{40}{10}$
$6x^2+7x^2+2$
$x^2+2x+7=0$
$4.56\cdot10^8$
$\left(-5\right)^2\cdot3+\left(-2\right)^3-3\cdot\left(-2\right)^4$
$x^3+\:x^2\:-4x\:-\:4\:$
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