$\frac{2x^2+5x-7}{x-2}$
$5+4\cdot4$
$\frac{3x-6}{5}<\frac{4x-2x^2}{10}$
$\int\:sec\:t\:\left(sect\:+\:tant\right)dt$
$3\sec^2\left(x\right)+7=11\tan\left(x\right)$
$-4\cdot100$
$\left(-24\right)\left(1-0.1\left(5\right)\right)^2$
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