$6t^2+36=0$
$\int_0^3\left(\sqrt{x+1}-1\right)^6dx$
$2xe+y;\:x=7;\:y=10$
$\frac{a^{-3}y^4}{x^{-3}}$
$1x+22^2$
$\left(a^2b^2+c^5\right)^2$
$\frac{dy}{dx}=x+1-y$
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