$\lim_{x\to\infty}\left(\frac{3\sin^2\left(\frac{6}{x}\right)}{\sin\left(\frac{4}{x}\right)\tan\left(\frac{3}{x}\right)}\right)$
$\sqrt[3]{x^5}y$
$\int\sqrt[2]{1-4y}dy$
$16z^{20}-72z^{10}x^3+81x^6$
$6^8\cdot6^3$
$\int8\sqrt{8x}dx$
$\left(3m+9n\right)\left(9n-3m\right)$
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