$2x+1=-x+4$

$4\tan\left(x\right)=\frac{\sqrt{3}}{\cos\left(x\right)^2}$

$\frac{1250}{2}$

$\frac{d}{dx}\frac{e^{2x^2-5x}}{3x^2-2x}$

$\lim_{x\to0}\left(1-\frac{cos\left(6x\right)}{\left(1-cos\left(8x\right)\right)}\right)$

$\left(\log\:_e\left(\frac{x}{52.69}+1\right)\cdot\:52.69\right)-x$

$z^3\left(5z^2-z^3+4\right)$