$4-2x-3$
$\left(4x^2+8y-3z\right)^3$
$16a^4+40a^2b^3+25b^6$
$-7x-8\ge-9+9x$
$\frac{dy}{dx}=y^2\cdot\left(3+x\right)$
$-\frac{100}{20}$
$-10\sqrt{x}-5\sqrt{x}+\frac{2}{3}\sqrt{y}-\frac{5}{2}\sqrt{y}$
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