$\left(4x\right)^2-y^2$
$\lim_{x\to\infty}\left(\frac{3x^2+4x}{5x^3+4x+6}\right)$
$190=-20c+a+b^3$
$\log_{64}\left(x\right)=\frac{1}{3}$
$2\cdot\sec^2\left(1\right)$
$2-2\left(9\right)+9$
$8x+12y$
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