$-\frac{1}{2}\log\left(c\right)$
$\left(7k+3x^2\right)^3$
$\sqrt[2]{-25}$
$m^2+6mn+9n^2$
$log3x^2-log3=2$
$\lim_{x\to\infty}\left(\frac{\ln\left(2^n+1\right)}{2^x}\right)$
$\frac{\left(+55\right)}{\left(+5\right)}$
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