$1-\cos x^2=\sin x$
$\int\left(\frac{x^2}{\left(4x^3+7\right)^5}\right)dx$
$4n^2+12-8n$
$x^3-6x^2-15x-8$
$\left(\frac{3}{4}a-2b\right)^2$
$\frac{dy}{dx}=\frac{\left(x+3\cdot y\right)}{\left(-3\cdot x+y\right)}$
$4x^2-12xy+6y^2$
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