$\lim_{x\to\infty}\left(\frac{e^{\frac{-1}{x^2}}}{x^2}\right)$
$\frac{9}{16}w^3-3w^3+4$
$5x^2+x-7$
$13=7+z$
$5^{12}:2^3$
$\frac{x^2-4}{x-1}$
$x^4-9x^2+4x+12$
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