$9\left(-2\right)^2\:+\:12\left(-2\right)\:+\:6$
$x=\sqrt{6-x}+3$
$\left(7b^2d^6\right)^2$
$\left(3\:a-b^{3\:x}\right)\left(3\:a+b\:^{3\:x}\right)$
$25x^8-1$
$x-2y-3z=-1$
$\left(\frac{x-0}{1-0}\right)\cdot\left(\frac{y-0}{2-0}\right)$
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