$f\left(x\right)=\ln\cos\left(2x\right)$
$\left(m+8\:\right)\:\left(\:m-3\right)$
$\frac{x^2-3x-10}{\:x^2+2x-35}\cdot\:\frac{x^2+4x-21}{x^2+9x+14}$
$7\:+\:9\:+\:8g$
$\frac{18}{3}-1$
$8sin^2a+2cosa=7$
$\left(-7\right)-\left(-13\right)\cdot5-2$
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