$\frac{xy^2}{x^2+1}dy=\frac{y^3}{y+2}dx$
$1+2+3+4+5+6+7$
$\frac{1}{2}f-3=1$
$\left(6v^3\right)^4$
$\frac{dy}{dx}\left(x^{\left(x^2\right)}\right)$
$x^2-\frac{2}{9}x$
$14\cdot8.50$
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