$10\:x\:-\:4\:.\left(\:x\:+\:1\right)\:\ge\:13\:+\:3\:x\:$
$9v+18$
$\int\frac{1}{x^2+7x+12}dx$
$\left(3m+4y\right)^3$
$255.000-72.000+185.000-180.000$
$\frac{3}{x}-\frac{1}{2}$
$\left(x\right)^4+x^3$
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