$4x^3+4x^2-x-1$
$6\cos^2x\tan x$
$\left(1\:+\:y^2\right)dx\:=\left(1-\sqrt{1+y^2}\right)\left(1+x^2\right)^{\frac{3}{2}}dy$
$cos4x\:+\:cos2xsin2x\:=\:cos2x$
$\frac{216w^{12}+343}{6y^4+7}$
$m^2-20m-300$
$49\cdot\left(-3\right)$
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