limx→0(2eex−4x−2x2+x−ln(1+x))\lim_{x\to0}\left(\frac{2e^{ex}-4x-2}{x^2+x-ln\left(1+x\right)}\right)x→0lim(x2+x−ln(1+x)2eex−4x−2)
∫(−24x2+25)dx\int\left(-\frac{24}{x^2+25}\right)dx∫(−x2+2524)dx
dydx(2y4+x4xy3)\frac{dy}{dx}\left(\frac{2y^4+x^4}{xy^3}\right)dxdy(xy32y4+x4)
1.09270986736\sqrt[36]{1.092709867}361.092709867
19x2+x+22219x^2+x+22219x2+x+222
24m−36c24m-36c24m−36c
8sec(x)csc(x)\frac{8\sec\left(x\right)}{\csc\left(x\right)}csc(x)8sec(x)
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