$\left(-5\right)x\left(+4\right)x\left(-3\right)x\left(+2\right)$
$-3x+\frac{7}{3}\le x+5$
$7x+2=16$
$\int\frac{1}{senx^4\cos x^2}dx$
$\left(5-5\right)\left(\sqrt{2}-\sqrt{5-3}\right)$
$\frac{1+\tan^2\left(x\right)}{\sec2\left(x\right)}=1$
$3x\:\left(x^3\:+2\right)^5$
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