$\frac{d^2y}{d^2x}=0$
$\left|23+15\right|$
$\left(\frac{27t^3}{8}\right)^{\frac{2}{3}}$
$8\cdot\left(-4\right)\cdot\left(-1\right)$
$\lim_{x\to2}\left(\frac{x^2-3x+2}{x^2-5x-6}\right)$
$\cos\left(x\right)^2=\frac{1+\cos\left(2x\right)}{2}$
$8\:+\:y^3\:2$
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