$-2x+5>x+3$
$x+2>3$
$\lim_{x\to\infty}\left(4xe^{-3x}\right)$
$250-2x^2$
$0.142a\:+\:0.142b\:=\:0.142b$
$\lim_{x\to0}\left(\frac{x-3}{x^2-3x}\right)$
$\lim_{x\to\frac{\pi}{2}}\left(5tanx\right)^{5cosx}$
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