$x^3-16x^2+76x-96$
$\frac{1}{2}\left(\frac{1}{3}x-2\right)\ge\frac{1}{4}$
$m^2-19m+48$
$\lim_{x\to\infty}\left(\frac{4x-7}{\sqrt{x^2+5}}\right)$
$4\left(-6x-4\right)-6=8+6x$
$2a+7^2$
$\lim_{x\to-\infty}\left(\sqrt{x^2+x}-\sqrt{x^2}\right)$
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