Simplifying
$8+x=7$
$\frac{1+x^2}{x^2\left(x-3\right)^2}$
$\int-24x^{-7}dx$
$\frac{\left(z^2\right)^6\left(z^{-3}\right)^2}{\left(z^5\right)^9}$
$\frac{125n^{12}-343b^6}{5n^4-7b^2}$
$mn\sqrt{88m^{15}n^{14}}$
$4=\frac{2}{7}x$
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