$\frac{12}{x\left(x^2+4\right)}$
$\lim\:_{x\to\:\:\:0}\left(\frac{x^x-1}{ln\:x\:+x-1}\right)$
$\lim_{x\to0}\left(\frac{sinx-cosx-x-1}{x^2}\right)$
$\left(x+3\right)\cdot2=54$
$\frac{4x^3+x^2-4}{x-1}$
$\frac{1-z^8}{1-z^4}$
$a^2+11a\:+18$
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