$\left(9x^3-6x^2+4x-8\right)-\left(3x-5x^2+6x-2\right)$
$1+sinx=2cos^2x$
$\left(12+9ab\right)\left(2-7a^2b\right)$
$\frac{w-5}{w^2-25}$
$5x^2+200x+750$
$x\:\frac{1}{2}\:-\:3x\frac{3}{2}\:+\:2x\frac{5}{2}\:=\:0\:$
$-\frac{4}{3}+x=\frac{2}{3}$
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