$\left(6x^4-3x^3-4x^2+2\right)\left(5x^2-8\right)$
$in\left(x+y\right)=\arctan\left(xy\right)$
$xy'-2y=x^3e^x$
$\frac{x^2-7x+4}{x-3}$
$\frac{b^{2\:}-9b-7}{b^2}$
$\int\:\frac{4x^2+3x+6}{x^2\left(x^2+3\right)}dx$
$6xy+8xy-xy+4yx-2xy$
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