$x^3-4x^2-5x-9\:para\:x\:=-3$
$\frac{125x^3-y^6}{5x-y^2}$
$2x+5=45$
$3x^2y-8x^2y$
$\left(a-b^2\right)^{-1.5}$
$\frac{2}{3}x-\frac{5}{6}=-\frac{5}{12}x+\frac{1}{4}$
$8xy-20y+6xy^2-15y^2$
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