$\left(9x^3-5x-5x^4-3+4x^2\right):\left(x-9\right)$
$6x-4w+3x-2w-6w$
$-6y+1-x^3+1+2y-3x^3$
$3a-4a+5a-7a+12a$
$f\left(x\right)=6\sqrt[3]{x}-\frac{6}{\sqrt{x}^3}$
$-11\:x\:16$
$-8\left(3u-1\right)-6$
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