ddx((x4+1)3(x−1)4x5)\frac{d}{dx}\left(\left(x^4+1\right)^3\left(x-1\right)^4x^5\right)dxd((x4+1)3(x−1)4x5)
(27x6)−23\left(27x^6\right)^{-\frac{2}{3}}(27x6)−32
∫((x−7)3)dx\int\left(\left(x-7\right)^3\right)dx∫((x−7)3)dx
y′′−(2x+3)xy′+(x+3)xy''-\frac{\left(2x+3\right)}{x}y'+\frac{\left(x+3\right)}{x}y′′−x(2x+3)y′+x(x+3)
4n2+15n+9=04n^2+15n+9=04n2+15n+9=0
0−2x(x−1)0-2x\left(x-1\right)0−2x(x−1)
∫x+32x(x−2)(x+2)dx\int\frac{x+3}{2x\left(x-2\right)\left(x+2\right)}dx∫2x(x−2)(x+2)x+3dx
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